Question

Log na base b, raiz quadrada
,x.y elevado a 3

Answer 1

log[b]  √(xy)³ 

= log[b]  (xy)^(3/2)

=( 3/2)*log[b] xy

=( 3/2)*log[b] x  + ( 3/2)*log[b] y

=( 3/2)*log x /log b  + ( 3/2)*log y/log b

=(3/2logb) * [log x + log y]