Question

Dadas as matrizes:

A-) 2 -3
4 -1

B-) 0 1
2 3

Calcule:
6A+3B

Answer 1

$\left[\begin{array}{cc}2&3\\4&1\\\end{array}\right] = 2\cdot 1 - 4\cdot 3 = 2-12 = -10$

$\left[\begin{array}{cc}0&1\\2&3\\\end{array}\right] = 0\cdot 3 - 1\cdot 2 = 0-2 = -2$

6A+3B = 6(-10)+3(-2) = -60 -6 =-66

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