Question

Me ajudem a resolver esses sistemas

0,6x+2,5y=10
-0,6x+2,5y=10


1,2x+3,5y=6,8
2,6x-3,5=0

Answer 1

0,6x + 2,5y = 10
-0,6x + 2,5y = 10
1,2x = 10
x = 10/1,2 = 8,3333333...

0,6x + 2,5y = 10
4,98 + 2,5y = 10
y = (10 - 4,98) / 2,5
y = 5,02 / 2,5
y = 2,008

o outro sistema:
1,2x + 3,5y = 6,8
2,6x - 3,5y= 0
-1,4x = 6,8
x = -4,85...

-5,82 + 3,5y = 6,8
12,62 = 3,5y
y= 3,60...