• Matéria: Matemática
  • Autor: 0034
  • Perguntado 8 anos atrás

BHASKARA, alguem?Ajuda? Pra hoje!

Anexos:

Respostas

respondido por: nestorwneto
0
Não dá para ver...

Publique com imagem maior

0034: a) x³-13x+42=0
0034: b)x²-11x+28=0
0034: c)x²-2x+1=0
0034: d) 2x-3x-10=0
nestorwneto: x^3 - 13x + 42
nestorwneto: X^3 – 13x + 42 =0
a = 1
b = -13
c = 42

Δ = b^2 – 4(a )(c)
Δ = (-13)^2 – 4 (1) (42)
Δ = 169 – 4 (42)
Δ = 169 – 168
Δ = 1
X1 = -b + - √ Δ / 2 (a)
X1 = - (-13) + √1 / 2(1)
X1 = 13 + 1 / 2
X1 = 14 / 2
X1 = 7

X2 = -b - √ Δ / 2 (a)
X2 = - (-13) - √1 / 2
X 2 = 13 – 1 / 2
X2 = 12 / 2
X2 = 6
nestorwneto: X^2 - 11x + 28 = 0
a = 1
b = -11
c = 28

Δ = b^2 – 4(a )(c)
Δ = (-11)^2 – 4 (1) (28)
Δ = 121 – 4 (28)
Δ = 121 – 112
Δ = 9
X1 = -b + - √ Δ / 2 (a)
X1 = - (-11) + √9 / 2(1)
X1 = 11 + 3 / 2
X1 = 14 / 2
X1 = 7

X2 = -b - √ Δ / 2 (a)
X2 = - (-11) - √9 / 2
X 2 = 11 – 3 / 2
X2 = 8 / 2
X2 = 4
nestorwneto: c)x²-2x+1=0
a = 1
b = -2
c = 1

Δ = b^2 – 4(a )(c)
Δ = (-2)^2 – 4 (1) (1)
Δ = 4 – 4
Δ = 0

X = -b + - √ Δ / 2 (a)

X1 = -b + √ Δ / 2 (a)
X1 = - (-2) + √0 / 2(1)
X1 = 2 + 0 / 2
X1 = 2 / 2
X1 = 1
nestorwneto: c)2x²-3x-10=0
a = 2
b = -3
c = -10

Δ = b^2 – 4(a )(c)
Δ = (2)^2 – 4 (2) (-10)
Δ = (2)^2 – (8) (-10)
Δ = 4 + 80
Δ = 84

X = -b + - √ Δ / 2 (a)

X1 = - b + √ Δ / 2 (a)
X1 = - (2) + √84 / 2(2)
X1 = - 2 + √84 / 4
X1 = 1.79

X2 = -b - √ Δ / 2 (a)
X2 = - (2) - √84 / 4
X2 = - 2.79
Perguntas similares