Question

Resolver essa equação do 2 grau, (x + 3)^2 =1

Answer 1

(x+3)²=1
x²+6x+3²=1
x²+6x+9-1=0
x²+6x+8=0

Aplicando a fórmula de Bhaskara:
Δ=b²-4a·c
Δ=36 - 4·8
Δ=36-32
Δ=4

x=-b+√Δ/2a
x1= -6+2/2 = -2
x2= -6-2/2 = -4