Question

Métodos para resolver esse problema ?

1,29x10^-05= e^Qv/0,0666 Qv é a variável.

Answer 1

1,29x10^-05= e^Qv/0,0666
1,29 . 10^-5 . 6,66 . 10^-2 = e^Qv
8,59.10^-7 = e^Qv
$Qv = log_{e} 8,59 . 10^{-7}$
Qv = -13,967

=)