Question

1/2ln(x-3)=ln(\sqrt{2x-1})

Answer 1

1/2ln(x-3) = ln[√(2x-1)]
ln[(x-3)^1/2] = ln[√(2x-1)]
(x - 3)^1/2 = √(2x - 1)
√(x - 3) = √(2x - 1)
x - 3 = 2x - 1
2x - x = -3 + 1
x = -2

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1/2ln(x-3) = ln[√(2x-1)]
1/2ln(-2-3) = ln[√(2.(-2)-1)]
1/2ln(-5) = ln[√(-4-1)]
1/2ln(-5) = ln[√(-5)]

Raiz de número negativo não existe.

Portant
S = {} ou Ф

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