Question

Calcule: (-5)²-4²+(1/5)^0
Sobre
3^-3+ 1

Answer 1

[(-5)²-4²+(1/5)^0] / (3^-3 + 1)
[25 - 16 + 1] / (1/27 + 1)
10 / (1/27 + 27/27)
10 / 28/27
10 . 27/28
270/28 = 135/14

=)

Answer 2

[(-5)²-4²+(1/5)⁰]
----------------------
    3⁻³+ 1

[25-16+1]
------------
1/3³ +1


   [9+1]
------------
1/27 +1


     10
------------
1/27 +27/27

     10
------------
   28/27

=10*27/28  =5*27/14 =135/14