Question

interpole seis termos aritméticos 62 e 97 ?????

Answer 1

(62, a2,a3,a4,a5,a6,a7,97)

a1=62; an = 97; n =8;
an= a1+(n-1).r;
a8= a1+(8-1).r;
a8= a1+7r;
97= 62+7r;
97-62= 7r;
35=7r;
7r=35;
r = 35/7;
r=5;
a2= a1+r; a2= 62+5; a2= 67;
a3=a2+r; a3= 67+5; a3= 72;

(62,67,72,77,82,87,92,97)