Question

X^2-x-3=6x+1-x^2

Alguem resolve?

Answer 1

[Tex]x^2 -x -3 = 6x + 1 -x^2 [/tex]

[Tex]x^2 + x^2 -x -3 -6x -1 = 0 [/tex]

[Tex] 2x^2 -7x -4 = 0 [/tex]

Answer 2

Olá

x² - x - 3 = 6x + 1 - x²

x² + x² - x - 6x - 3 - 1 = 0 

2x² - 7x - 4 = 0 

Δ = (-7)² - 4 * 2 * (-4)

Δ = 49 + 32

Δ = 81

x = - (-7) + - √81 / 2*2

x' = 7 + 9 / 4

x' = 4

x" = 7 - 9 / 4

x" = - 2 / 4

x" = - 1 / 2

S = {4, - 1/2}