Question

P.A de 8 termos ,sendo A1=16 e r=6?

Answer 1

P.A de 8 termos ,sendo A1=16 e r=6?


An = A1 + (n - 1)*r
An = 16 + (2 - 1)*6
An = 16 + 1*6
An = 16 + 6
An = 22

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PA = {16,22,

An = A1 + ( n - 1)*r
An = 16 + (3 - 1)*6
An = 16 + 2 * 6
An = 16 + 12
An = 28

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An = A1 + ( n - 1)*r
An = 16 + (4 - 1)*6
An = 16 + 3*6
An = 16 + 18
An = 34


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An = A1 + (n - 1)*r
An = 16 + ( 5 - 1)*6
An = 16 + 4 * 6
An = 16 + 24
An = 40


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An = A1 + (n - 1)*r
An = 16 + ( 6 - 1)*6
An = 16 + 5 *6
An = 16 + 30
An = 46
28

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An = A1 + ( n - 1)*r
An = 16 + ( 7 - 1)*6
An = 16 + 6 * 6
An = 16 + 36
An = 52


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An = A1 + ( n - 1)*r
An = 16 + ( 8 - 1)*6
An = 16 + 7 * 6
An = 16 + 42
An = 58



RESPOSTA :

PA = { 16,22,28,34,40,46,52,58}