Question

dada a função quadrática f(x)=3x^2-4x+1, determine
a)f(1)
b)f(0)
c)f(√2)
d)f(-2)
e)f(h+1)

Answer 1

a) f(1)
f(1)= 3.(1)²-4.1+1
f(1)= 3.1-4+1
f(1)= 3-4+1
f(1)= 0

b) f(0)
f(0)= 3.(0)²-4.0+1
f(0)= 0-0+1
f(0)= 1

c) f(√2)
f(√ 2)= 3.(√ 2)²-4.(√ 2)+1
f(√ 2)= 3.2-4.√ 2+1
f(√ 2)= 6-4√ 2+1
f(√ 2)= 7-4√ 2

d) f(-2)
f(-2)= 3.(-2)²-4.(-2)+1
f(-2)= 3.4+8+1
f(-2)= 12+9
f(-2)= 21

e) f(h+1)
f(h+1)= 3.(h+1)²-4.(h+1)+1
f(h+1)= 3.(h²+2h+1)-4h-4+1
f(h+1)= 3h²+6h+3-4h-3
f(h+1)= 3h²+2h

Espero ter ajudado!