Question

ME AJUDEM A RESPONDER A 17 -A

Answer 1

A=log 2√2 /log 2  +log 10 /log 0,01

********2√2 =√8=√2³=2^(3/2)
********0,01 =10^(-2)

A=log [2^(3/2) ] /log 2  +log 10 /log 10^(-2)

A=(3/2)* log [2 /log 2  +log 10 /(-2)*log 10

A=3/2 -1/2 =2/2=1 é a resposta