Question

me ajudem urgente não estou conseguindo resolver 17_B

Answer 1

A = [3 ^(log₂ 10) ] * log₃ 2 + log₀,₀₄ 125

#####  y=3 ^(log₂ 10)
#####  log₂ y = log₂  3 ^(log₂ 10)
#####  log₂ y =(log₂ 10)  * log₂  3
#####  log y/log2 =(log 10)/log 2  * log 3 /log 2
#####  log y =(log 10)  * log 3 /log 2
#####  log y =log 3 /log 2
#####  y=log 3/log 2
#####  

A = [log 3/log 2] * log₃ 2 + log 125/log 0,04

A = [log 3/log 2] * log 2/log 3 + log 125/(log 4/100)

##### 0,04 =4/100=1/25 =5⁻²
##### 125=5³

A = 1 + log 5³/log 5⁻²

A = 1 +3 log 5/(-2)log 5

A =1 -5/2 =-3/2