Question

Calcule o perímetro do triângulo de vértices (3,7) (2,1) (8,2)

Answer 1

Dab² = (3 -2 )² + (1 -7) ²

DAB = 1 + 36

DAB raiz de 37

 

(dAC)² = (8-3)² + (2-7)²

(dAC)² = 25 + 25

(dAC)² = raiz de 50

 

(dBC)² = (8 -2 )² + (2 -1)²

(dBC)² =  36 + 1

(dBC)² = raiz de 37

 

P = Dac + Dab + Dbc

P = raiz de 50 + raiz de 37 + raiz de 37

P = raiz de 50 + 2 raiz de 37