Question

qual o valor de x e y ????.

Answer 1

Usando teorema de Pitágoras
a²=b²+c²

a) 5² = 4² + y²
25 = 16 + y²
16 + y² = 25
y² = 25 - 16
y² = $\sqrt{9}$
y = 3

35² = 21² + x²
21² + x² = 35²
x² = 35² - 21²
x² = 1225 - 441
x² = 784
x = $\sqrt{784]$
x = 28

b) y² = 4² + 3²
y² = 16 + 9
y² = 25
y = 5

15² = 12² + x²
12² + x² = 15²
x² = 15² - 12²
x² = 225 - 144
x² = 81
x = $\sqrt{81]$
x = 9