Question

fórmula centesimal H2SO4

Answer 1

Massa molar do H2SO4 = 1.(2) + 32 + 16(4) = 2 + 32 + 64 = 98 g

%H = 2 g / 98 = 0,02 = 2%
%S = 32 / 98 = 0,326  = 32,6%
O = 64 / 98 = 0,654  = 65,4 %

Answer 2

Massa molar:

H=1g/mol

S=32g/mol

O=16g/mol

Massa molar do composto

2×1+32+4×16=2+32+64=98g/mol

$\%H=\dfrac{2}{98}\times100\approx2,04\%$

$\%S=\dfrac{32}{98}\times100\approx32,65\%$

$\%O=\dfrac{64}{98}\times100\approx65,30\%$

Fórmula centésimal:

$H_{2,04\%}S_{32,65\%} O_{65,30\%}$