Question

Dada a função f(x)=x^2+5x-4,determine: a)f(1) b)f(2) c)f(-1) d)f(0,2) e)f(-6)f)f(-10)

Answer 1

a- f(1)= 1^2+5*1-4=2
b- F(2)=2^2+5*2-4=10
c- f(-1)= -1^2+5*(-1)-4=-8
d-f(0,2) = 0,2^2 +5*0,2-4 = 1,04-4=-2,96
e-f(-6)= -6^2+5*(-6) - 4 = 2
f- f(-10)= -10^2 +5*(-10) -4= 46