Question

Integral de (ax^4 + bx^3 + 3c) dx

Answer 1

⌠(ax^4+bx^3+3c)dx= 
⌠(ax^4)dx+ ⌠(bx^3)dx+⌠(3c)dx= 
a⌠(x^4)dx+ b⌠(x^3)dx+ 3c⌠dx= 
a(x^5)/5 + b(x^4)/4 +3cx +d