Question

resolva as equaçoes biquadradas 2x^2- 3ax+a^2

Answer 1

equações literais

2x²-3ax+a²=0

a=2
b=-3a
c=a²
Δ=b²-4ac
Δ=(-3a)²-4(2)(a²)
Δ=9a²-8a²
Δ=a²
√Δ=√a²=± a

$x= \frac{-b\pm \sqrt{delta} }{2a} = \frac{-(-3a)\pm \sqrt{a^2} }{2.2} = \frac{3a\pm a}{4}$

$x'= \frac{3a+a}{4} = \frac{4a}{4} =a$

$x"= \frac{3a-a}{4} = \frac{2a}{4} = \frac{a}{2}$

S={ a/2,a}