Question

lim raiz de 25 - x² / x -5 x tende a 5 elevado -

Answer 1

$\lim_{x\rightarrow-5}\frac{25-x^2}{x-5}=\\\\\lim_{x\rightarrow-5}\frac{(5+x)(5-x)}{-(5-x)}=\\\\\lim_{x\rightarrow5^{-1}}\frac{(5+x)}{-1}=\\\\\lim_{x\rightarrow-5}-(5+x)=\\\\\lim_{x\rightarrow-5}-5-x=\\\\-5-(-5)=\\-5+5=\\\boxed{0}$