Question

Me ajudem a resolver.

Log de 16V2 na base 2.

Answer 1

$log_{2}(16 \sqrt{2} ) = x \\ {2}^{x} = 16 \sqrt{2} \\ {2}^{x} = {2}^{4} \times {2}^{ \frac{1}{2} } \\ x = 4 + \frac{1}{2} \\ x = \frac{9}{2}$