Question

AJUDA POR FAVOR URGENTE

No triangulo retângulo, calcule o senα, cosα, tgα, senβ, cosβ e tgβ:

a= 15
b = 9
c= 12

Answer 1

$sen( \alpha ) = \frac{9}{15} \\simplificar \: por \: 3 \\ sen ( \alpha ) = \frac{3}{5} \\ \\ \cos( \alpha ) = \frac{12}{15} \: ( \div 3) \\ \cos( \alpha ) = \frac{4}{5} \\ \\ \tg = ( \alpha ) \frac{ \frac{3}{5} }{ \frac{4}{5} } = \frac{3}{5} \times \frac{5}{4} = \frac{15}{20} ( \div 5) = \frac{3}{4}$
$sen( \beta )= \frac{12}{15} = \frac{4}{5} \\ \cos( \beta ) = \frac{9}{15} = \frac{3}{5} \\ \tg( \beta ) = \frac{ \frac{4}{5} }{ \frac{3}{5} } = \frac{4}{5} \times \frac{5}{3} = \frac{4}{3}$