Question

como posso resolver?

x^2-4x-24=0?

Answer 1

x^2 - 4x = 24
x^2 - 4x + (4/2)^2 = 24 + (4/2)^2
(x-2)^2 = 28
x - 2 = ±√28
x = 2±√28
x = 2±2√7
So x = 2+2√7 and 2-2√7

Answer 2

x² -4x -24 = 0

Δ = b² -4ac
(-4)² -4 . -24
16 + 96
112

x = (4 ± 4√7)/2

x' = 2 +2√7

x'' = 2 -2√7