Question

dada a funçao quadratica f(x)=-x2 +6x-5 determine as cordenadas verticis do grafico da parabola definida

Answer 1

f(x)=-x²+6x-5

Yv = -b²-4ac / 4a
Yv = (-6)²-4.(-1).(-5) / 4.(-1)
Yv = 36 - 20 / (-4)
Yv = 16 / (-4)
Yv = -4

Xv = -b / 2a
Xv = -(-6) / 2 . (-1)
Xv = 6 / (-2)
Xv = - 3