Question

Quanto termos existem na PG (3, 6, ..., 1536) ? Calculo.

Answer 1

A1=3
An= 1536
n=? (Quantidade de termos)
r=2

$1536=3.2^{n-1}$

$\frac{1536}{3} =2^{n-1}$

$512=2^{n-1}$

$2^{9} =2^{n-1}$

n-1= 9 ---> n=10