Question

Se sen x = 3/4, com pi/2 menor x menor pi, determine sec x, cotg x e tg x

Answer 1

senx²+cosx²=1
(3/4)²+cosx²=1
9/16 +cosx²=1
cosx²= -9/16 +1
cosx² -9 +16/16
cosx²= 7/16
cosx= √7/16
cosx= √7/4

secx=1/√7/4
secx= 1 × 4/√7
secx= 4√7/7

cotgx= √7/4/3/4
cotgx= √7/4 × 4/3
cotgx= 4√7/3

tgx= 3/4/√7/4
tgx= 3/4 × 4/√7
tgx= 3√7

é isso, espero ter ajudado!!