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Fórmula de Báskara:
y=3x^2+5x-2=0 a=3, b=5, c=-2
-b±√b²-4*a*c/2*a
-5±√5²-4*3*(-2)/2*3
-5±√25+24/6
-5±√49/6
-5±7/6
x1=-5+7/6=2/6=1/3
x2=-5-7/6=-12/6=-6/3=-2
Im=(1/3,-2)
y=3x^2+5x-2=0 a=3, b=5, c=-2
-b±√b²-4*a*c/2*a
-5±√5²-4*3*(-2)/2*3
-5±√25+24/6
-5±√49/6
-5±7/6
x1=-5+7/6=2/6=1/3
x2=-5-7/6=-12/6=-6/3=-2
Im=(1/3,-2)
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