Question

-x²+10x-25=0 ME AJUDEM URGENTE? com bhaskara

Answer 1

-x² +10x -25 = 0           a=-1         b=10           c=-25

Δ = b² - 4.a.c
Δ = 10² -4.-1.-25
Δ = 100 -100
Δ = 0        terá apenas uma raíz

x = -b / 2a
x = -10 / 2.-1
x = -10 / -2
x = +5

Answer 2

Resposta:

$S=\{5\}$

Explicação passo-a-passo:

$-x^{2} +10x-25=0\times(-1)\\x^{2} -10x+25=0\\\\a=1\\b=(-10)\\c=25$

$\Delta=b^{2} -4ac\\\Delta=(-10)^{2}-4\times1\times25\\\Delta=100-100\\\Delta=0$

$x=\frac{-b\pm\sqrt{\Delta} }{2a} \\\\x=\frac{-(-10)\pm\sqrt{0} }{2\times1} \\\\x=\frac{10\pm0}{2}$

$x_{1} =\frac{10+0}{2} =\frac{10}{2} =5\\\\x_{2}=\frac{10-0}{2}=\frac{10}{2} =5$