Question

Determine a soluçao da equaçao 5x auquadrado- 3x - 2=0 Use

Answer 1

5x² - 3x - 2 = 0

Δ= (-3)² - 4 . 5 . (-2)
Δ= 9 + 40
Δ= 49

X= -(-3) ±√49 / 2.5
X= 3 ± 7 / 10
X'= 3 + 7 / 10 = 10 / 10 = 1
X"= 3 - 7 / 10 = -4 / 10 (÷2) = -2 / 5

S={ 1 , -2/5 }

Answer 2

Vamos lá :

5x² - 3x - 2 = 0

a = 5 ; b = - 3 ; c = - 2

Δ = b² - 4ac
Δ = (- 3)² - 4.5.(- 2)
Δ = + 9 + 40
Δ = + 49        ⇒⇒√Δ = 7

Aplica a formula de Bhaskara :

x = (- b ± √Δ)/2a

x = (- (- 3) ± 7)/2*5
x = (+ 3 ± 7)/10

x' = (3 + 7)/10 = 10/10 = 1

x'' = (3 - 7)/10 = - 4 ÷ 2/10 ÷ 2 = - 2/5

S = {- 2/5 , 1}

Espero ter ajudado !!!