Question

RESOLVA:

a) log4 $\sqrt{32}$

Answer 1

Vamos lá :

$log_{4}~ \sqrt{32} ~=~ x \\ \\ 4^{x} = \sqrt{32} \\ \\ (2^{2})^{x} = \sqrt{2^{5}} \\ \\ 2^{2x} = 2^{\frac{1}{2}*5} \\ \\ 2^{2x} = 2^{\frac{5}{2}} \\ \\ 2x = \frac{5}{2} \\ \\ x = \frac{\frac{5}{2}}{2} \\ \\ \boxed{\boxed{x = \frac{5}{4}}}$

Espero ter ajudado !!!