Question

(ax^2) - (a) + (bx^2) + (2b) + (cx) + (2c)

Answer 1

(ax^2) - (a) + (bx^2) + (2b) + (cx) + (2c)

x²*(a+b) +cx  - (a+2b+c)=0

x'= [-c+√(c²+(4a+4b)(a+2b+c))]/2(a+b)

x''= [-c-√(c²+(4a+4b)(a+2b+c))]/2(a+b)

Fatorando

(x-[-c+√(c²+(4a+4b)(a+2b+c))]/2(a+b)) * [x-[-c-√(c²+(4a+4b)(a+2b+c))]/2(a+b))