Question

equação biquadrada -x ao quadrado+x+12=0

Answer 1

-x² + x + 12 = 0

a= -1
b = 1
c = 12

Δ = b² -4 .a .c 

Δ = 1² -4 . (-1) . (12)
Δ = 1 + 4 . 12
Δ = 1 + 48
Δ = 49

$\mathtt{\dfrac{-b~+- \sqrt{\Delta}}{2~.~a}}~~=~~ \dfrac{-1~+- \sqrt{49}}{2~.~(-1)}}~~=~~\dfrac{-1~+- ~7}{-2}} \\ \\ \\ \mathtt{x' = \dfrac{-1 + 7}{-2}~~=~~ -\dfrac{6}{2} = \boxed{- 3} } \\ \\ \\ \mathtt{x'' = \dfrac{-1 -7}{-2}~~=~~ \dfrac{-8}{-2}~~~~=~~\boxed{4}}$

Resposta : S{ 4  e  -3 }

Answer 2

-x²+x+12=0

Δ=1²-4*-1*12
Δ=1+48
Δ=49  √Δ=7

$x1= \frac{-1+7}{2*-1}= \frac{6}{-2} = -3$

$x2= \frac{-1-7}{2*-1}= \frac{-8}{-2}=4$

Bons Estudos!!