Question

1- Determine a medida de cada ângulo em destaque nos triângulos.

(cálculos)

Answer 1

A)
â=180°-65°
â=115°
^b=180°-132°
^b=48°
^c+48°+115°=180°
^c=180°-163°
^c=17°
^d=180°-17°
^d=163°

B)
^k=180°-125°
^k=55°
^l=150°(OPV)

150°*2=300°
360°-300°=60°
60/2=30°

^j+125°+30°=180°
^j=180°-155°
^j=25°
î=180°-25°
î=155°

Answer 2

A) 
â=180°-65°
â=115°
^b=180°-132°
^b=48°
^c+48°+115°=180°
^c=180°-163°
^c=17°
^d=180°-17°
^d=163°

B)
^k=180°-125°
^k=55°
^l=150°(OPV)

150°*2=300°
360°-300°=60°
60/2=30°

^j+125°+30°=180°
^j=180°-155°
^j=25°
î=180°-25°
î=155°