Question

escreva as expressões abaixo na forma a+bi= (4-i)+i(6+3i)i
(2-i)2/(3+i)2
3-1/
4+5i

Answer 1

a)
$(4-i)+i(6+3i)i =4-i-6-3i=10-4i$
b)
$\dfrac{(2-i)2}{(3+i)2}=\dfrac{2-i}{3+i}\times\dfrac{3-i}{3-i}=\dfrac{5-5i}{10}=\dfrac{1}{2}-\dfrac{i}{2}$
c)
$\dfrac{3-1}{4+5i}=\dfrac{2}{4+5i}\times\dfrac{4-5i}{4-5i}=\dfrac{8-10i}{41}=\dfrac{8}{41}-\dfrac{10i}{41}$

Espero ter ajudado!