Question

O vertice da parabola da função F (x) = x2 - 6 x + 4

Answer 1

$f(x)=x^2-6x+4$

$a=1~~~~~~b=-6~~~~~~c=4$

$x_{\text{V}}=\dfrac{-b}{2\cdot a}$

$x_{\text{V}}=\dfrac{-(-6)}{2\cdot1}~\hookrightarrow~x_{\text{V}}=\dfrac{6}{2}~\hookrightarrow~\boxed{x_{\text{V}}=3}$

$y_{\text{V}}=\dfrac{-\Delta}{4\cdot a}$

$\Delta=b^2-4\cdot a\cdot c$
$\Delta=(-6)^2-4\cdot1\cdot4$
$\Delta=36-16$
$\Delta=20$

$y_{\text{V}}=\dfrac{-20}{4\cdot1}~\hookrightarrow~y_{\text{V}}=\dfrac{-20}{4}~\hookrightarrow~\boxed{y_{\text{V}}=-5}$

$\text{V}(3,-5)$

Answer 2

Vamos lá :

f(x) = x² - 6x + 4

 a = 1 ; b = - 6 ; c = 4

Δ = 36 - 16 = 20

Yv = - Δ/4a = - 20/4 = - 5

Xv = - b/2a = 6/2 = 3

V(- 5 , 3)

Espero ter ajudado !!!