• Matéria: Matemática
  • Autor: sarasilva15sant
  • Perguntado 8 anos atrás

Determine:
N) 2x+4y=16
-3x+5y=9


O) 2x+3y=10
5x+6y=22

Respostas

respondido por: Thihefi
2
n)\\\\
 \left \{ {{2x+4y=16} \atop {-3x+5y=9}} \right. \\
 \left \{ {{2x+4y=16\  .3} \atop {-3x+5y=9\  .2}} \right. \\
 \left \{ {{6x+12y=48} \atop {-6x+10y=18}} \right. \\\\
Somando:\\\\
22y = 66\\\\
y = \dfrac{66}{22}\\\\
y = 3\\\\
Substituindo:\\\\
2x+4y=16\\
2x + 4.3  = 16\\
2x = 16 - 12\\
2x = 4\\
x = 2\\

o)\\\\
 \left \{ {{2x+3y=10} \atop {5x+6y=22}} \right. \\
 \left \{ {{2x+3y=10\  .(-2)} \atop {5x+6y=22\ \ \ \ \ \ \ }} \right. \\
 \left \{ {{-4x-6y=-20} \atop {5x+6y=22\ \ \ \ \ }} \right. \\\\
Somando:
\\\\
x = 2\\\\
Substituindo:\\\\
2x + 3y = 10\\
2.2 + 3y = 10\\
4 + 3y = 10\\
3y = 10 - 4\\
3y = 6\\
y = 2

=)
Perguntas similares