• Matéria: Matemática
  • Autor: edson319
  • Perguntado 8 anos atrás

resolva as equaçoes do 2 grau ×2-12×+35=0


Anônimo: x2 ou 2x?

Respostas

respondido por: caio0202
6
x² - 12x + 35 = 0

a = 1
b = -12
c = 35

Δ = b² -4 .a . c
Δ = (-12)² -4 . 1 . 35
Δ = 144 -4 . 35
Δ = 144 - 140
Δ = 4 

\mathtt{\dfrac{-b +-~\sqrt{\Delta}}{2~~.~~a}~~~=~~ \dfrac{-(-12) +-\sqrt4}{2~~.~~1}~~=~~\dfrac{12 +-~2}{2}} \\ \\ \\ \mathtt{x' = \dfrac{12+2}{2}~~=~~\dfrac{14}{2}~~=~~\boxed7} \\ \\ \\ \mathtt{x'' = \dfrac{12-2}{2} ~~=~~\dfrac{10}{2}~~=~~\boxed5} \\ \\ \\ \boxed{\boxed{\mathtt{Resposta: S: 5~~e~~7}}}
respondido por: ivanildoleiteba
5
Olá, boa noite ☺

Resolução:

x² - 12x + 35 = 0.

Coeficientes:

a=1 , b= -12 , c= 35.

Valor de delta:

Δ=b²-4.a.c
Δ=(-12)²-4.1.35
Δ=144 - 140.
Δ=4.

Valores de x:

\\ x= \dfrac{-b \pm  \sqrt{\Delta} }{2a} 
\\
\\ x=\dfrac{-(-12) \pm  \sqrt{4} }{2} 
\\
\\ x=\dfrac{12\pm 2 }{2}
\\
\\ x'= \dfrac{12+ 2 }{2}= \dfrac{14}{2} =7 \\
\\ x''=\dfrac{12- 2 }{2}= \dfrac{10}{2} = 5

S={7,5}.

Bons estudos :)


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