Question

dados log 2= a e log 3= b determime log 0,06

Answer 1

0,06 = 6 x 10^ (-2) 

log 6 x 10^ (-2) = log6 + log 10^(-2) = 

log6 = 0,778 
log 10^(-2) = - 2 

log 6 x 10^ (-2) = 0,778 + ( - 2) = 0,778 - 2 = -1,22

Answer 2

Log 0,06

= Log 6 / 100
= Log 6 - Log 100
= Log 2 * 3 - 2
= Log 2 + Log3 - 2
= a + b - 2