Question

(2/5)^-3 – (7,1)^0 + o,4²

Answer 1

Vamos lá :

(2/5)⁻ ³ - (7,1)⁰ + 0,4²

= (5/2)³ - (1) + (4/10)²
= 125/8 - 1 + (2/5)²
= 125/8 - 1 + 4/25

Mmc(8 , 25) = 200

= (125*25)/200 - 200/200 + (4*8)/200

= (3125 - 200 + 32)/200

= 2957/200 →→→ Respostaa

Espero ter ajudado !!