Question

calcule a distancia entre os pontos I (1/2, - 1/3) e J (5/2, 1/3).

Answer 1

d = √(∆x)² + (∆y)²

∆x = 1/2 - 5/2 = -4/2 = -2

(∆x)² = (-2)² = 4

∆y = -1/3 -1/3 = -2/3

(∆y)² = (-2/3)² = 4/9

(∆x)² + (∆y)² = 4 + 4/9 = 36/9 + 4/9 = 40/9

d = √(40/9)

d =√40/√9

d = √40/3

√40 = √4.√10 = 2.√10

d = (2√10)/3

Answer 2

d= √(x2-x1)^2+(y2-y1)^2

d= √(5/2-1/2)^2+(1/3+1/3)^2

d= √(4/2)^2+(2/3)^2

d= √2^2+(4/9)

d= √4+4/9

d= √36+4/9

d= √40/9

d= √2^2*2*5/9

d= 2√10/3