Question

Resolva a seguinte equação expotencial R:

2^+1 + 2x -1=40

Answer 1

$2^{x+1}+2^{x-1}=40 \\ \\ 2^x.2^1+2^x.2^{-1}=40 \\ \\ 2.2^x+2^x. \frac{1}{2}=40 \\ \\ 2.2^x+\frac{2^x}{2}=40 \\ \\ 4.2^x+2^x=80 \\ \\ 5.2^x=80 \\ \\ 2^x= \frac{80}{5} \\ \\ 2^x=16 \\ \\ 2^x=2^4 \\ \\ x=4 \\ \\\\ S=\{4\}$