Question

x^2-20x+100=0 e a formula de baskara

Answer 1

x^2-20x+100=0
delta=b^2-4.a.c
delta=(-20)^2-4.1.100
delta=400-400
delta=0
x=-b-/+ raiz de delta / 2a
x=-(-20)-0/2.1
x=20-0/2
x=20/2
x=10