• Matéria: Matemática
  • Autor: dudinnhacampos
  • Perguntado 8 anos atrás

Se r é resultado da operação 10^5+[(2.10^24.10^6)/(4.10^22)]+1,5.10^4

Respostas

respondido por: ProfAmaral
3
Verifique se a sua questão é essa.
\ \ \ 10^5+\Big[\frac{2\cdot10^{24}\cdot10^6}{4\cdot10^{22}} \Big]+1,5\cdot10^4\\ \\=10^5+\Big[\frac{2\cdot10^{22}\cdot10^{2} \cdot10^6}{4\cdot10^{22}} \Big]+1,5\cdot10^4\\ \\=10^5+\Big[\frac{2\cdot10^{2} \cdot10^6}{4} \Big]+1,5\cdot10^4\\ \\=10^5+\Big[\frac{2}{4}\cdot10^{2+6} \Big]+1,5\cdot10^4\\ \\=10^5+0,5\cdot10^{8} +1,5\cdot10^4\\ \\=1\cdot10^5+0,5\cdot10^{3}\cdot10^{5} +1,5\cdot10^4\cdot \frac{10}{10} \\ \\=1\cdot10^5+500\cdot10^{5} +0,15\cdot10^{4+1}\\
\\=1\cdot10^5+500\cdot10^{5} +0,15\cdot10^{5}
\\=10^5\cdot(1+500+0,15)\\
\\=501,15\cdot10^5\\
\\=5,0115\cdot10^2\cdot10^5\\
\\=5,0115\cdot10^7

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