Question

Me ajudem por favor?

Answer 1

log 4 16 + log 3 9 - log 0,001

(4^x = 16) + (3^x = 9) - (10^x = 0,001)

(4^x = 4^2) + (3^x = 3^2) - (10^x = 10^-3)

( x = 2 ) + ( x = 2 ) - ( x = - 3 )

2 + 2 - 3

4 - 3

1