Question

Calcule:
$( - 3) {}^{ - 1} ( - 1) {}^{ - 3}$
$2 {}^{ - 4} - 2 {}^{2}$
$( {4}^{ - 1} + {2}^{ - 3} ) {}^{ - 1}$
$(6 {}^{ - 2} \times 3 {}^{2} ) - 1$

Answer 1

Vamos lá!
$(- \frac{1}{3} ).(-1)^{3} = - \frac{1}{3} . -1 = \frac{1}{3}$
$( \frac{1}{2} )^4-4= \frac{1}{16} -4= \frac{1-64}{16} = \frac{-63}{16}$
$\frac{1}{ \frac{1}{4}+( \frac{1}{2})^3 } = \frac{1}{ \frac{1}{4}+ \frac{1}{8} } = \frac{1}{ \frac{2+1}{8} }= \frac{1}{ \frac{3}{8} } = \frac{8}{3}$
$(( \frac{1}{6} )^2 .9)-1=( \frac{1}{36} .9)-1=( \frac{9}{36} )-1= \frac{1}{4} -1= \frac{1-4}{4} = \frac{-3}{4}$
Boa sorte! Espero ter ajudado.