Question

resolva as equaçoes ex ponenciais
a)2³×+¹ x 4²×+³=8³×

Answer 1

a)$2^{3x+1}$ × $4^{2x+3}$ = $8^{3x}$
$2^{3x+1}$ × $(2^{2})^{2x+3}$ = $(2^{3})^{3x}$
$2^{3x+1}$ × $2^{2*(2x+3)}$ = $2^{3*3x}$
$2^{3x+1}$ × $2^{4x+6}$ = $2^{9x}$
$2^{3x+4x+1+6}$ = $2^{9x}$
$2^{7x+7}$ = $2^{9x}$

$7x+7 = 9x$
$9x-7x = 7$
$2x = 7$
$x = \frac{7}{2}$