Question

Me ajudem, prfv:

a) 2t elevado a 3+4= -50
b) 4x+3+x elevado a 2= 4x+12
c) 3s elevado a 2-12=2s elevado a 2-7

d)7- raiz de x=3

Answer 1

a)
$2t^{(3+4)} = -50$
$2t^{7} = -50$
$t^{7} = - \frac{50}{2}$
$t^{7} = -25$
$t = \sqrt[7]{-25}$

b)
$4x+3+x^2 = 4x+12$
$4x-4x+x^2 = 12-3$
$x^2 = 9$
$x = \sqrt {9}$
$x=$±$3$

c)  $3s^{2-12} = 2s^{2-7}$
$3s^{-10} = 2s^{-5}$
$\frac{ s^{-10} }{ s^{-5} } = \frac{2}{3}$
$s^{-10-(-5)} = \frac{2}{3}$
$s^{-5} = \frac{2}{3}$
$\frac{1}{ s^{5} } = \frac{2}{3}$
$3 = 2 s^{5}$
$\frac{3}{2} = s^{5}$
$s = \sqrt[5]{ \frac{3}{2} }$ ou $s = \sqrt[5]{1,5}$

d)
$7- \sqrt{x} = 3$
$- \sqrt{x} = 3-7$
$- \sqrt{x} = -4$
$\sqrt{x} = 4$
$x = 4^{2}$
$x = 16$

Espero ter ajudado.