Question

A) 4. (X-1) = 4+2.(X-1)
B) 7y -3.(y-2) = 3. (y+4)

Answer 1

$a) 4(x-1)=4+2(x-1) \\ 4x-4=8(x-1) \\ 4x-4=8x-8 \\ 4x-8x=8+4 \\ -4x=-4 \\ x= \frac{ - 4}{ - 4} \\ 1$

$b) {7y}^{2} - 14y - 3y + 6 = 3y + 12 \\ {7y}^{2} - 17y + 6 = 3y + 12 \\ {7y}^{2} - 17y - 3y = 12 - 6 \\ {7y}^{2} - 20y = 6$