Question

log de 9 na base x-3 =2

Answer 1

$\textit{Resolu\c{c}\~ao}\Rightarrow \left\{\begin{matrix} (x-3)^{2}=9 \\ x^{2} -6x+9=9 \\ x^{2} -6x=0 \\ x(x-6)=0\\ x=0 \ ou \\ x-6=0 \ \ x=6\\ \\ x-3>0\\ x>3\\ & \boxed{\boxed{x=6}}& \end{matrix}\right.$